Body projected vertically upwards, crosses a point in t1 seconds and further t2 seconds then velocity of projection is
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s
A
=ut−
2
1
gt
2
(att=t
1
,t
2
)
So, s
A
=ut
1
−
2
1
gt
1
2
−(1)
s
A
=ut
2
−
2
1
gt
2
2
−(2)
Equating (1)and(2)
⇒u(t
1
−t
2
)=
2
1
g(t
1
2
−t
2
2
)
⇒u=g
2
(t
1
+t
2
)
Max ht=
2g
u
2
=
4×2g
g
2
(t
1
+t
2
)
2
=2g(
4
t
1
+t
2
)
2
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