Body sliding down an inclined plane having an angle theta if the coefficient of friction is u the acceleration of the body down the incline plane is
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The scenario is as shown below:
where fg=m.a is the force due to gravity. Now as θ increases fg_incl increases where fg_incl is the component of force along the inclined plane and it is given by
fg_incl=fg∗sinθ
Now for θ=60∘
fg_incl=fg∗sin60∘=0.866∗fg
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