Question

body start from rest and move with acceleration of 2m/s². find the distance covered by the body in the 10th second of its motion​

Answer 1

Answer:

Explanation

Given :-

A body starts from rest

So,

u (initial velocity) = 0

acceleration = 2m/s²

To find :-

Distance travelled in 10 seconds

Solution :

We know that distance travelled in nth second =

Sn = u + a/2(2n-1)

____________________[Put values]

\large{\boxed{n \: = \: 10}}

n=10

S10 = 0 + 2/2(2*10-1)

S10 = 20-1

S10 = 19

mark as brainliest

S10 = 19 m