Question

body starting from rest acquires a velocity of 10 m/S' in 5 seconds. Calculate (a) the acceleration (b) the distance covered by the body in 5 seconds​

Answer 1

initial velocity = 0 m/s

final velocity = 10 m/s

time = 5 seconds

(a) need to find ==> acceleration

given ==> initial velocity, final velocity and time

procedure ==> a = (v-u)/t

a = (10-0)/5

a = 10/5 = 2 m/s^2

therefore, the acceleration of the body is 2 m/s^2

(b) need to find ==> distance

given ==> acceleration, time, initial velocity and final velocity

procedure ==> s = ut + 1/2 at^2

s = 0*5 + 1/2 * 2 * 5 * 5

s = 0 + 5*5

s = 0 + 25

s = 25 m

therefore, the distance covered by the body is 25 metres

Answer 2

Hi,

Given:

Initial velocity(u)=0m/s

Final velocity(v)=10m/s

Time(t)=5 s

To Find:

a)Acceleration of the body(a)

b)Distance covered(s)

Solution:

a)

Acceleration of a body is given by the equation

a=(v-u)/t

Substitute the given datas in the equation

We get,

a=(10-0)/5

a=2m/s²

b)

Distance covered by a body is given by the equation

s=ut+1/2 at²

Substitute the given datas in the equation

We get,

s=0×5+1/2×2×5²

s=25m

Hope this helps you.