Body travelling along a straight line transferred one third of the total distance with velocity 4 metre per second the remaining part of the distance was covered with a velocity of 2 metre per second for half the time and with the process is metre per second for the other half of time what is the average velocity over the whole motion?
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Answer:
A body travelling along a straight line traversed one third of the total distance with a velocity 4ms−1 . The remaining part of the distance was covered with a velocity 2ms−1 for the other half of time .
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Answer:
4 ms^ (-1)
Explanation:
Let (s) be the total distance travelled by body. If t1 is the time taken to over first one thirdd
distance, then t1=s/34=s12
Let t−2 be the time for each of the remaining two journeys. Then
2s3=2t2+6t2=8t−2
or t2=2s2×8=s12
Average velocity →taldistance→taltime
= s/( t-1 + 2 t_2) = s/( 9 s//12) = 2 ( s// 12) = 4 ms^(-1)`.
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