Question

body travelling with velocity of 100 metre per second accelerates uniformly at the rate of 10 M per second squalre for a period of 20 seconds calculate the velocity and the distance travelled in 30 seconds

Answer 1

Answer:

velocity = 300m/s

distance traveled =7000 m

Explanation:

given-

initial velocity, u = 100m/sec

acceleration, a =10m/ sec^2

time, t = 20sec

by laws of motion,

v= u +at

v= 100 + 10 ×20

v= 300m/sec

and

s = ut + 1/2at^2 , where s is displacement

s = 100×20 + 1/2×10×20×20

s = 2000 + 2000

s = 4000 m

now after 20 sec acceleration vanishes and body perform uniform motion

distance traveled in next 10 sec = 300 × 10

=3000 m

so total distance = 7000 m

since motion is uniform then velocity after 20 sec remains constant .