Question

Body weight 45 kg on the surface of the earth what will be its weight on the surface of the Mars whose mass is 1/9 and radius is 1/2 that of earth

Answer 1

Answer:

200 N

Explanation:

g=GM/R²

M becomes 1/9 and R becomes 1/2

So, g becomes 4/9 times as that on Earth

Now weight = mg' = 45*10*4/9

= 200 N

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