Question

Bohr magneton is the magnetic moment of​

Answer 1

Answer:

The Bohr magneton is the magnitude of the magnetic dipole moment of an electron orbiting an atom with such angular momentum. According to the Bohr model, this is the ground state, i.e. the state of lowest possible energy.

Explanation:

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Answer 2

Answer:

The Bohr magneton is the magnitude of the magnetic dipole moment of an electron with some angular momentum orbiting in an atom.

Explanation:

Bohr Magneton is used to express magnetic moments at the atomic scale..

• Bohr magneton $\mu _B$ is a physical constant. It is a natural unit for expressing the magnetic moment of an electron caused by either its orbital or spin angular momentum.
• Bohr magneton is given by:-

          $\mu _B=\frac{eh}{2m_e}$

        Where $m_e$ is the mass of  an electron

       e is the electrical charge

       h is the Plank's constant

• The value of Bohr magneton is equal to 9.27 × 10⁻²⁴JT⁻¹ in its S.I. units.
• The magnetic moment due to the orbital motion of an electron as a magnitude is given by,

       $m_l=\sqrt{l(l+1)\mu_B}$      where, $l$ is orbital quantum number

• An electron has a magnetic moment due to  intrinsic spin and its magnitude given by the spin magnetic moment formula,

         $m_S=\sqrt{S(S+1)\mu_B}$         where, S is spin quantum number, (S=1/2)

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