boiling bionts of different 1 m solutions
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Na3PO4 in water
(0.010m * 4 ions) = 0.040
0.020 m KCl in water
(0.020 m * 2 ions) = 0.040
(0.020m CaBr2 in water boils higher, while 0.020 m HF in water boils lower)
(0.010m * 4 ions) = 0.040
0.020 m KCl in water
(0.020 m * 2 ions) = 0.040
(0.020m CaBr2 in water boils higher, while 0.020 m HF in water boils lower)
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