Question

boiling point of benzene and toulene solution is 130°c. calculate ratio of pb° and pT°if mole fraction of benzene in solution is 0.4?

Answer 1

Answer:

Given P=179X

B

+92

For pure C

6

H

6

,X

B

=1

∴P

B

o

=179+92=271mm

For pure C

7

H

8

,X

B

=0

∴P

T

o

=179×0+92=92mm

Now, P

M

=P

B

o

X

B

+P

T

o

X

T

=(271×

12+8

12

)+(92×

12+8

8

)

=199.4mm

as, Moles of C

6

H

6

=

78

936

=12

Moles of C

7

H

8

=

92

736

=8

Now, mole fraction of C

6

H

6

in vapour phase of initial mixture X

B

1

=

199.4

162.6

and that of toulene, X

T

1

=

199.4

36.8

∴

X

T

1

X

B

1

=

36.8

162.6

=4.418