Question

Boiling point of benzene is 353.35 K. Kb for benzene is 4.25 K.Kg/mol. If certain amount of substance is dissolve in benzene , boils at 354 K, then molality of substance is

Answer 1

The elevation in the boiling point ΔT

b

​

=354.11−353.23=0.88 K.

The expression for the molar mass of the solute is

M

2

​

=

ΔT

b

​

×w

1

​

K

b

​

×w

2

​

×1000

​

Substitute values in the above expression.

M2=

0.88×90

2.53×1.8×1000

​

=57.5 g/mol

Hence, the molar mass of the solute is 57.5 g/mol

Hope it works

Please mark my answer as BRAINLIST

Stay Home Stay Safe

​