Physics, asked by thakurvikash3572, 1 year ago

Boltzmann constant k=1.38×10^-23 j/k the energy associated with helium atom at the surface of the sun where surface temperature is 6000 k is

Answers

Answered by lidaralbany
4

Answer: E = 1.24\times10^{-19} J

Explanation:

Given that,

Boltzmann constant k = 1.38\times 10^{-23} J/K

Temperature T = 6000 K

We know that,

The Kinetic energy of a molecule is direct proportional to the temperature of the surface.

The energy is

E = \dfrac{3}{2}kT

E = \dfrac{3}{2}\times 1.38\times10^{-23}J/K\times 6000 K

E = 1.24\times10^{-19} J

Hence, the energy associated with helium atom at the surface of the sun is E = 1.24\times10^{-19} J.

Answered by Anonymous
2

The ideal gas law can be written in terms of the number of molecules of gas: PV = NkT, where P is pressure, V is volume, T is temperature, N is number of molecules, and k is the Boltzmann constant k = 1.38 × 10–23 J/K. A mole is the number of atoms in a 12-g sample of carbon-12.

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