Physics, asked by vamsi93, 1 year ago

Bond angle of water molecule

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Answered by Anonymous

1

However, because the two non-bonding pairs remain closer to the oxygen atom, these exert a stronger repulsion against the two covalent bonding pairs, effectively pushing the two hydrogen atoms closer together. The result is a distorted tetrahedral arrangement in which the H—O—H angle is 104.5°.

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