Chemistry, asked by danger1614, 1 year ago

Bond dissociation enthalpy of H₂, Cl₂ and HCl are 434 , 242 and 431 kJ mol⁻¹ respectively. Enthalpy of formation of HCl is :
(a) 93 kJ mol⁻¹
(b) – 245 kJmol⁻¹
(c) – 93 kJmol⁻¹
(d) 245 kJmol⁻¹

Answers

Answered by Shrutidesai004
4

Answer

option (c).........

Answered by XxfrankensteinxX
0

<b>HeYaA mAtE

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