Question

Bond distance in HF is 9.17 x 10-11m. Dipolemoment of HF is 6.104 x 10-30 Cm. Thepercentage of ionic character in HF will be(electron charge = 1.60 x 10-19 C)​

Answer 1

Answer:

Explanation:

Dipole moment = q(charge of electron) * r(bond length)