Question

Bond energy of F2 is 150 KJ /mol .calculate the minimum frequency of phton to break this bond.

Answer 1

Answer:

Since, in the question the bond dissociation energy of the F2 atom is given as 150 x 10^3 J/mol hence the energy required for breaking the F-F bonds will be (150*10^3)/6.022*10^22.

As, we know that the value of energy E is hf where f is the frequency and h is the planks constant so the value of the frequency will be f = E/h = (150*10^3)/6.022*10^22*6.626*10^-34 which will approximately be 3.76*10^14 hertz.