Question

bond order of benzene

Answer 1

HEYA !!!! HERE IS UR ANSWER. bond order = 1/2 (bonding - anti bonding)

for C-C sigma bond
BO =1/2(2-0)=1

for C-C pi bond
BO= 1/2(6-0)=3

for one C-C pi bond
BO = 3/6=0.5

for a single C-C bond in benzene ,the total BO=sigma + pi= 1+0.5= 1.5

HOPE THIS WILL HELP U

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Answer 2

The bond order of a bond is half the difference between the number of bonding and antibonding electrons.

BO = ½(B – A)

The C-C σ Bonds

Each C-C σ bond is a localized bond. It has 2 bonding electrons and 0 nonbonding electrons.

σ BO = ½(B – A) = ½(2 – 0) = 1

The C-C π Bonds

Benzene has 6 molecular π orbitals.

Of these, three are bonding and three are anti-bonding. The six π electrons go into the three bonding orbitals.

π BO = ½(B – A) = ½(6 – 0) = 3

This is the π bond order for 6 C-C bonds.

For one C-C π bond, BO = 3/6 = 0.5.

For a single C-C bond in benzene, the total BO = σ + π = 1 + 0.5 = 1.5