Question

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Divide the Polynomial x^4-6x^3-26x^2+138x-35x by x^2-4x+1. ^ it meant exponent.



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Answer 1

HEY THERE!!

$\huge{\bold{QUESTION:-}}$



Divide the Polynomial x⁴-6x³-26x²+138x-35x by x²-4x+1.



$\huge{\bold{SOLUTION:-}}$



$\begin{tabular}{r|llll} & x^2-2x-35 \\\cline{2-3}x^2-4x+1 & x^4-6x^3 -26x^2+138x-35 \\\cline{1-1} & x^4-4x^3+x^2\\ \cline{2-3}& \: \: \: \: -2x^3-27x^2+138x-35 \\& \: \: \: \:-2x^3+8x^2-2x \\ \cline{2-3}&& \\& -35x^2+140x-35 \\& \: -35x^2+140x-35\\\cline{2-3}&&0 \quad \: \: \end{tabular}$

Hence, Quotient: x²-2x-35

Remainder: 0

Answer 2

Please see above image.