Math, asked by swayamprava12, 1 month ago

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Chapter: 09 ; Linear Equation
Subject: Maths
Class: 08.
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Answers

Answered by dchakradhari55
2

Answer:

Let us consider

Son’s age = X

Two years ago son’s age = X – 2

His Father’s age at that time = 3(X – 2)

Present age of Father = 3X – 6 + 2

The present age of Father = 3X – 4

Two years hence father’s age = 3X – 4 + 2

Two years hence father’s age = 3X – 2

Two years hence son’s age = X + 2

Given:

5 × (X + 2) = 2 × (3X – 2)

5X + 10 = 6X – 4

X = 14

Son’s present age X = 14 years.

Father’s present age = (3 × 14) – 4

Father’s present age = 38 years.

Answered by pari9054
35

\:\boxed{\sf{{}{Answer: - }}}

\mathfrak\pink{2 \: years \: ago}

■ Father's Age :- 3x

■ Son's Age :- x

\mathfrak\pink{2 \: years  \: later}

1

➡ 2 × (3x + 4 ) = 5 × ( x + 4 )

➡ 6x + 8 = 5x + 20

➡ 6x - 5x = 20 - 8

➡ x = 12

➟ Present age of father = 3x + 2

= 3 × 12 +2 = 38 years

➟ Present age of son = x + 2 = 12 + 2 = 14 years

✥✧═══════━•❁❀❁•━═══════✧✥

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