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Chapter: 09 ; Linear Equation
Subject: Maths
Class: 08.
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Answers
Answer:
Let us consider
Son’s age = X
Two years ago son’s age = X – 2
His Father’s age at that time = 3(X – 2)
Present age of Father = 3X – 6 + 2
The present age of Father = 3X – 4
Two years hence father’s age = 3X – 4 + 2
Two years hence father’s age = 3X – 2
Two years hence son’s age = X + 2
Given:
5 × (X + 2) = 2 × (3X – 2)
5X + 10 = 6X – 4
X = 14
Son’s present age X = 14 years.
Father’s present age = (3 × 14) – 4
Father’s present age = 38 years.
■ Father's Age :- 3x
■ Son's Age :- x
1
➡ 2 × (3x + 4 ) = 5 × ( x + 4 )
➡ 6x + 8 = 5x + 20
➡ 6x - 5x = 20 - 8
➡ x = 12
➟ Present age of father = 3x + 2
= 3 × 12 +2 = 38 years
➟ Present age of son = x + 2 = 12 + 2 = 14 years
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