Bonjour! Please help me with this!!
=_=
Attachments:
Anonymous:
assam beauti ke liye famous hai n??
oh..
sorry...i just heard that...so i asked
is it u in dp??
looking so cute yaar
ur welcome
Answers
Answered by
1
Heya....Ur answer...
We know that, R = V2 /P
Hence resistance of 1st bulb = (250)2 / 200 = 625/2
resistance of 2nd bulb = (250)2 / 100 = 625
Total resistance of the circuit when the bulbs are connceted in series = 625/2 + 625 = 1875/2 ohm
Therefore, total power consumed in the circuit , P = (250)2 / (1875/2) = 67 watt
We know that, R = V2 /P
Hence resistance of 1st bulb = (250)2 / 200 = 625/2
resistance of 2nd bulb = (250)2 / 100 = 625
Total resistance of the circuit when the bulbs are connceted in series = 625/2 + 625 = 1875/2 ohm
Therefore, total power consumed in the circuit , P = (250)2 / (1875/2) = 67 watt
yaa P maane power..
Resistance=Potential difference^2 /Power hoi
yupe
:) :)
action
Answered by
1
hello dear...✔️✔️
here is d solution ☺️☺️
We know that, R = V2 /P
Hence resistance of 1st bulb = (250)2 / 200 = 625/2
resistance of 2nd bulb = (250)2 / 100 = 625
Total resistance of the circuit when the bulbs are connceted in series = 625/2 + 625 = 1875/2 ohm
Therefore, total power consumed in the circuit , P = (250)2 / (1875/2) = 67 watt
hope it helps u❤️❤️❤️
here is d solution ☺️☺️
We know that, R = V2 /P
Hence resistance of 1st bulb = (250)2 / 200 = 625/2
resistance of 2nd bulb = (250)2 / 100 = 625
Total resistance of the circuit when the bulbs are connceted in series = 625/2 + 625 = 1875/2 ohm
Therefore, total power consumed in the circuit , P = (250)2 / (1875/2) = 67 watt
hope it helps u❤️❤️❤️
Similar questions