Question

Bonjour!!!!


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Two oxide of metal contains 27.6% and 30% oxygen.

If the formula of first oxide is M3O4.

Find that of second ?


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Answer 1

Answer:

bonjour amiè

Let atomic mass of  Metal = m

    M3  O4  =>  molecular mass = 3m+4*16

  % of Oxygen:  64/(3m+64)  = 0.276            =>   m = 55.96 (nearly 56)

Let 2nd Oxide be:   Mx Oy

      % of oxygen = 16 y / (56 x + 16 y)  = 0.30 

          => 11.2 y = 16.8 x   

          => 2  y = 3 x

2nd oxide =  M2 O3