Boolean function to minimum number of literals..a) (x+y)(x+y'). B). x+y+x'z+yz
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Explanation:
a)
(x + y)(x + y')
= x.x + x.y' + y.x + y.y'
= x + x(y + y') + 0
= x + x
= x
b)
x + y +x'z + yz
= x + x'z + y + yz
= x + x'z + y(1 + z)
= x + z + y
Properties used
- a.a = a
- a + a' = 1
- a.a' = 0
- a + 1 = 1
- a + a'b = a + b
Hope it helps :-)
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