Question

Boolean function to minimum number of literals..a) (x+y)(x+y'). B). x+y+x'z+yz

Answer 1

Explanation:

a)

(x + y)(x + y')

= x.x + x.y' + y.x + y.y'

= x + x(y + y') + 0

= x + x

= x

b)

x + y +x'z + yz

= x + x'z + y + yz

= x + x'z + y(1 + z)

= x + z + y

Properties used

• a.a = a
• a + a' = 1
• a.a' = 0
• a + 1 = 1
• a + a'b = a + b

Hope it helps :-)