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12. If 5 tan B=0 evaluate
5 SinB-3C0SB/5sin B+ 2cosB
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Answer:
-3/2
Step-by-step explanation:
5sin B-3CosB/5sin B + 2 Cos B
divide numerator and denominator by CosB
(5 (sin B/Cos B) - 3 CosB/CosB )/((5 sinB/CosB)+2Cos B/Cos B)
= 5TanB-3/5TanB+2
=5×0-3/5×0+2
-3/2
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