Question

borazine hydrolysis slowly according to the following reaction weight of borazine required to form 0.2 moles of h3bo3​

Answer 1

Answer:

The naswer is 12.4 g.

Explanation:

Weight can be determined from the number of moles by using the formula.

Number of moles = mass  (g) / molar mass (g/mol)

Hence we are given with the number of miles i.e = 0.2 moles

Calculate the molar mass of H3BO3 = 3 X atomic mass of H + 1 X atomic mass of B + 3 X atomic mass of O

                                                         = 3 x 1 + 11 + 3 x 16

                                                         =  3 + 11 + 48

                                                       = 62 g/mol

Put the values in above formula :

 Mass (g)   = number of moles x molar mass of a substance  (g/mol)

                 = 0.2 x 62 = 12.4 g