bore hora koi txt karo
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Answer:
5sinФ = 12cosФ
sinФ/cosФ = 12 / 5
tanФ = 12/5
so perpendicular =12x , base = 5x
hypotenuse = 13x(Pythagoras theorem)
secФ = hypotenuse/base = 13x/5x = 13/5
cosecФ = hypotenuse/perpendicular = 13x/12x = 13/12
HOPE IT HELPS!!!
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