Question

Boron has 2 isotopes b-10 and b-11 . The average atomicbmass of boron is found to be 10.80 u . Calculate the percentage of abundance of these isotopes

Answer 1

Explanation:

let % abundance of b-10 be x

% abundance of b-11 be (100-x)

average atomic mass =10.80

10*x+11*(100-x)/100=10.80

10x+1100-11x=1080

-x =1080-1100

-x =-20

x=20

% abundance of b-10 be 20%

% abundance of b-11 be 100-20 =80%