Question

boron has two isotope 10_b and 11_b whose relative abundance are 20% and 80% respectively atomic weight of boron is ?​

Answer 1

Answer:

Average atomic weight = $\dfrac { 20×10+80×11 }{ 100 }$

= $\dfrac { 200+880 } { 100 }$

= $\dfrac { 1080 } { 100 }$

= 10.8g