Boron has two isotopes ,5B ( power) 10
and ,5B¹¹ whose % abundances are 19.6, 80.4 respectively.
What is average atomic mass of Boron?
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Answer:
Let, 100 mol of sample contains x mol of
5
B
10
and 100−x mol of
5
B
11
.
The average atomic weight of boron is 10.81.
Hence, 10.81=
100
x×10+(100−x)×11
1081=10x+1100−11x
19=x
100−x=100−19=81
Thus, 100 mol of sample contains 19 mol of
5
B
10
and 81 mol of
5
B
11
.
Thus, the ratio is 19:81.
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