Question

boron has two isotopes,B-10 and B-11 .The average atomic mass of boron is found to be 10.80u. calculate the % of abundance of these isotopes

Answer 1

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Answer 2

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*******Answer*******

B10 and B11

Let B10 = x%

B11 = (100-x)%

Average atomic mass = 10x + 11(100-x)/100 = 10.80


10x + 11(100-x) = 1080


10x + 1100 - 11x = 1080

-x = - 20

x = 20

∴ B10 = 20% and B11 = (100-20)= 80%




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