boron has two isotopes b-10 and b-11.the percentage abundance of b-10 is 19.8% and that of b-11 is 80.2%.calculate the relative atomic mass (ar) of boron.
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Answer:10.80
Explanation:
10 * 19.8 + 11 * 80.2/100
198 + 882.2/100
10.80.
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