Boron has two isotopes b10 and b11 the average atomic mass of boron is ? percentage value of B10=20% and B11=80% what is the atomic mass of boron
Answers
Answered by
7
Avg amu ==> ( m1A + m2B ) / A+B
where m1 = isotope 1
A = percentage of 1
m2 = isotope 2
B = percentage of 2
where m1 = isotope 1
A = percentage of 1
m2 = isotope 2
B = percentage of 2
Attachments:
Answered by
3
AAM = 20×10 + 80×11 ÷ 100
=200 + 880 ÷ 100
=1080 ÷ 100
=10.8 amu
Similar questions