Chemistry, asked by Bunty6435, 1 year ago

Boron has two isotopes with masses 10.13 u and 11.01 u and abundance of 19.77% and 80.23% respectively. what is the average atomic mass of boron?

Answers

Answered by Anonymous
3

10.13×19+80×11.01÷100

=10.73

Answered by Ladylaurel
3

\boxed{\mathfrak{Average \ atomic \ mass \ of \ boron = 10.836 \ u}}

༅Average atomic mass of boron=10.836 u

Abundance of 10.13 u mass isotope = 19.77%

Abundance of 11.01 u mass isotope = 80.23%

༅Atomic mass of (1)×%abundance+Atomic mass of (2)×%abundance

average atomic mass = 10.836

⟹Average Atomic Mass= 100

10.13×19.77+11.01×80.23

⟹Average atomic mass= 100

200.2701+883.3323

⟹Average Atomic Mass= 100

1083.6024

⟹Average Atomic Mass=10.836u

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