Question

Boron is unable to form BF$_6^{-3}ion$Explain​

Answer 1

Explanation:

• Due to non- availability of d orbitals Boron is unable to expand its octet.
• Therefore the maximum covalence of boron cannot exceed 4

Answer 2

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Boron does not have d orbitals. Because of this, it is not possible for the element to expand on its octet. This causes the maximum covalence of boron to be restricted to 4. Beyond this value, boron will become unstable and thus, cannot form BF$_6^{-3}ions$