Boron is unable to form BF63-.why
Answers
Answered by
66
Boron does not have d-orbitals in its valence shell, and therefore the maximum covalency of boron can not exceed. Thus, boron is unstable to form BF63- ions.
Answered by
15
Hey dear,
● Answer -
Boron is unable to form (BF6)3- because of non-availability of
● Explaination -
- Aluminum from group 13 have extra d-orbital in its valence shell and can extend its octet to form (AlF6)3- ion.
- But boron doesn't have vacant d-orbital and thus can't exceed its octet beyond covalency 4.
- Therefore, (BF6)3- doesn't exist.
Hope this helped you...
● Answer -
Boron is unable to form (BF6)3- because of non-availability of
● Explaination -
- Aluminum from group 13 have extra d-orbital in its valence shell and can extend its octet to form (AlF6)3- ion.
- But boron doesn't have vacant d-orbital and thus can't exceed its octet beyond covalency 4.
- Therefore, (BF6)3- doesn't exist.
Hope this helped you...
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