Question

Boron occurs in nature in the form of two isotopes having atomic masses 10 and 10.2. What

are the percentage abundances of these isotopes in a sample of a boron having average

atomic mass of 10.8?




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Answer 1

Answer:

Percentage abundance of B-11 isotope = 80 %.

see the attachment for step-by-step solution.

Explanation:

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Answer 2

Question:-

Boron occurs in nature in the form of two isotopes having atomic masses 10 and 10.2. What are the percentage abundances of these isotopes in a sample of a boron having average atomic mass of 10.8?

Solution:-

Let the percentage abundance of first isotopes be $\frac{10}{5}$B = x

Hence the percentage abundance of second isotopes is $\frac{11}{5}$B = 100 - x.

Average atomic mass =

$\frac{x × 10 + (100 - x) × 11}{100}$

1080 = 10x + 1100 - 11x

or,

x = 20

Hence the %abundance of the two isotopes are 20% and 80%.