Chemistry, asked by maryam00001, 7 months ago


Boron with atomic number 5 has two naturally occurring isotopes. Calculate the
percentage abundance of B10 and "B11 from the following information.
Average atomic mass of boron
= 10.81 amu
Isotopic mass of B10
= 10.0129 amu
Isotopic mass of B11
=11.0093amu ​

Answers

Answered by bhupenderSinghrajput
0

Answer:

bro I think it would be 2nd options

Explanation:

isotopic mass of B10 =10.0129amu

Similar questions