Chemistry, asked by prajesh8838, 1 year ago

Both metals mg and fe reduce copper metal from a solution having cu2+ ions as,mg(s) + cu 2+(s) =cu+ mg2+ k1= 6 x 10^90 fe(s) + cu2+=cu(s)+fe2+ k2 = 3 x 10^26which metal will remove cu?* ion from the solutionto greater extent?

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Answered by sania12347
2

Both metals mg and fe reduce copper metal from a solution having cu2+ ions as,mg(s) + cu 2+(s) =cu+ mg2+ k1= 6 x 10^90 fe(s) + cu2+=cu(s)+fe2+ k2 = 3 x 10^26which metal will remove cu?* ion from the solutionto greater extent?

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