Both of Lalima and Romen clean their garden.If Lalima works for 4 days and Romen works for 3 days then (2)/(3) part of the work is completed.Again if Lalima works for 3 days and Romen works for 6 days then (11)/(12) part of the work is completed.Let us form the Simultaneous equations and write the number of days required to complete the work separately by Lalima and Romen by calculating the solution.
Answers
Step-by-step explanation:
I hope it helps....
all the best
Answer:
Lalima required 12 days for complete the work and Romen required 9 days to complete (verified answer)
Step-by-step explanation:
Let the whole work done by Lalima be x and Romen be y
work done by lalima in 1 day= 1÷x
= 1/x
work done by lalima in 4 days= 1/x ×4
=4/x
work done by Romen in 1 day= 1÷y
= 1/y
work done by the Romen in 3 days=1/y×3
=3/y
Both worked and completed 2/3 part of work
4/x+3/y=2/3 - eq-1
again,
work done by lalima in 3days= 1/x×3
=3/x
work done by the Romen in 3 days=1/y×6
=6/y
Both worked and completed 11/12 part of work
3/x+6/y=11/12 -eq2
4/x+3/y=2/3 equation,1 [by method of elimination]
3/x+6/y=11/12 equation.2
multiplying equation 1 by 3 and equation.2 by 4
12/x+9/y=2
12/x+24/y=11/3
- - - {by subtracting}
___________
0x - 15y= -5/3 cancelling-from both sides
or y=9
putting the value of 9 in equation 1,we get
4/x+3/9=2/3
4/x=2/3-1/3
4/x=1/3
1/x=1/12
x=12
Therefore Lalima required 12 days for complete the work and Romen required 9 days to complete