Math, asked by madhur2534, 2 months ago

both of my digits are even , one of my digits is 4 . my tens place is twice the amount of my ones place I am less than 70 . who am I ?

step by step explanation
answer if you know ​

Answers

Answered by khandelwalsnehlata55
2

Answer:

48

Step-by-step explanation:

if we take 4 in ones place then tens is twice as ones meaning 8 the number will be 84 which is more than seventy now if we reverse the case tens as 4 then ones is 8 which is 48 and less than 70 and also it fulfils all the conditions given above

Answered by MysticSohamS
7

Answer:

hey here is your answer

pls mark it as brainliest

so here we go

Step-by-step explanation:

let the required two digit number be 10x+y

so here it is said that one of its digit is 4

so let digit at tens place ie x be 4

thus x=4

so then according to second condition

x=2y

4=2y

ie y=2

so our assumed two digit number=10x+y

=(10×4)+2

=40+2

=42

hence 42 is required two digit number which is less than 70

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