both of question 15......do it..plz
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[15] [b] = M.I = 2MR^2/5
ACCORDING to the theorem of parallel axes, the moment of inertia of a body about any axis is equal to the sum of the moment of the inertia of the body about a parallel axis passing through its center of mass and the product of its mass and the square of the distance between the two parallel axis. the MI about a tangent of a sphere = MR^2 /5 +MR^2= 7MR^2 /5
hope this helps u
one thing more the last two pics will help u in the 15 [a] question if u figure them out okay the black on isn't clear but the things that are written are important and the last one is just to show how it looks
have a nice exam
ACCORDING to the theorem of parallel axes, the moment of inertia of a body about any axis is equal to the sum of the moment of the inertia of the body about a parallel axis passing through its center of mass and the product of its mass and the square of the distance between the two parallel axis. the MI about a tangent of a sphere = MR^2 /5 +MR^2= 7MR^2 /5
hope this helps u
one thing more the last two pics will help u in the 15 [a] question if u figure them out okay the black on isn't clear but the things that are written are important and the last one is just to show how it looks
have a nice exam
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