Question

Both p and q vary directly with each other. When p is 10 and q is 15,
following is not a possible pair of corresponding values of p and q?​

Answer 1

Answer:

15 and 20 is not possible pair

option (i) is correct

Step-by-step explanation:

since P and Q are directly vary with each other,

P = kQ where k is a constant

when P=10, Q=15

⇒ 10=k(15)

⇒ k= 10/15

⇒ k= 2/3

\therefore\:P=\frac{2}{3}Q∴P=

3

2

Q

when Q=20

P=\frac{2}{3}(20)P=

3

2

(20)

P=\frac{40}{3}P=

3

40

when Q=30

P=\frac{2}{3}(30)P=

3

2

(30)

P=20P=20

when Q=3

P=\frac{2}{3}(3)P=

3

2

(3)

P=2P=2

when Q=7.5

P=\frac{2}{3}(7.5)P=

3

2

(7.5)

P=5P=5

⇒ 15 and 20 is not possible pair

hope this is helpful

thank you