both ques with solution
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27.
Force - [M][L]^1^/[T]^2= 10 N - Eq.(1)
Energy - [M][L]^2/[T]^2 = 100 J --Eq.(2)
Velocity -[L][T]^-1 = 5 m/s --Eq.(3)
(I am not putting square brackets from now bcuz it takes time, plz understand it without the brackets)
Eq.1/Eq.2 =
[M][L]/[T]^2/ [M][L]^2/[T]^2 = 10/100
L/L² = 10/100
L = 100/10 = 10 m
Putting in Eq.3
10 /T = 5
T = 10/5 = 2 s
Similarly find mass by substitution,
it will be 4 kg
So, the answer is (B)
28. Dimensional formula of Inductance, L=[ML²Q^-2]
Dimensional formula of Capacitance, C=[M^-1L^-2T^2Q^2]
Dimensional formula of √LC =[[ML^2Q^−2][M^−1L^−2T^2Q^2]]^1/2
Dimensional formula of √LC=[T^2]^1/2
Dimensional formula of √LC=T
So, Dimensional formula of LC = T²
Force - [M][L]^1^/[T]^2= 10 N - Eq.(1)
Energy - [M][L]^2/[T]^2 = 100 J --Eq.(2)
Velocity -[L][T]^-1 = 5 m/s --Eq.(3)
(I am not putting square brackets from now bcuz it takes time, plz understand it without the brackets)
Eq.1/Eq.2 =
[M][L]/[T]^2/ [M][L]^2/[T]^2 = 10/100
L/L² = 10/100
L = 100/10 = 10 m
Putting in Eq.3
10 /T = 5
T = 10/5 = 2 s
Similarly find mass by substitution,
it will be 4 kg
So, the answer is (B)
28. Dimensional formula of Inductance, L=[ML²Q^-2]
Dimensional formula of Capacitance, C=[M^-1L^-2T^2Q^2]
Dimensional formula of √LC =[[ML^2Q^−2][M^−1L^−2T^2Q^2]]^1/2
Dimensional formula of √LC=[T^2]^1/2
Dimensional formula of √LC=T
So, Dimensional formula of LC = T²
simran25:
N is equal to force
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