Question

Both questions
Plz answer fast

Answer 1

the 1st answer is here ⬆⬆⬆⬆⬆

the second answer is ⤵⤵⤵⤵⤵⤵

$x \cos\alpha = 1 \\ => x = \frac{1}{ \cos \alpha } \\ => \: x = \sec \alpha \\ => {x}^{2} = { \sec}^{2} \alpha \\ \\ then \: \tan \alpha = y \\ \: \: \: \: \: \: \: \: y^2= { \tan }^{2} \alpha \\ \\ so \: \: {x}^{2} - {y}^{2} = { \sec }^{2} \alpha - { \tan}^{2} \alpha \\ \: \: {x}^{2} - {y}^{2} = 1$

the 1st answer is 9 ✔✔✔✔✔

2nd answer is 1 ✅✅✅✅✅

✨✨✨hope it helps✨✨✨✨