both the sums give me answers
Answers
The cuboid shape has six sides called faces. Each face of a cuboid is a rectangle. Also assume that the given side of the cube in the question as a. Hence, the total surface area of the cube of side 7 cm is 294 cm2.
this is total surface area of cube
In a cube, the length and width are the same, so both sides will be 7 cm, yielding an area of 49 square centimeters. The surface area of a 7 cm cube will be 294 cm2 .
this is lateral surface area of cube
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^2
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^22400=6×a×a
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^22400=6×a×a2400/6=a×a
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^22400=6×a×a2400/6=a×a400=a×a
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^22400=6×a×a2400/6=a×a400=a×aa=√400
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^22400=6×a×a2400/6=a×a400=a×aa=√400a=20 cm
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^22400=6×a×a2400/6=a×a400=a×aa=√400a=20 cmW. K. T length of the diagonal of a cube=√3 ×a
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^22400=6×a×a2400/6=a×a400=a×aa=√400a=20 cmW. K. T length of the diagonal of a cube=√3 ×aSo, the length of a diagonal =√3×20
. K. T total surface area of a cube=6a^2, square units (6 a square) where a is the length of the edge of a cube.So, it's given that area=2400cm^2Area=6a^22400=6×a×a2400/6=a×a400=a×aa=√400a=20 cmW. K. T length of the diagonal of a cube=√3 ×aSo, the length of a diagonal =√3×20=20√3 cm