Math, asked by jk41338, 11 months ago

Both you have to prove plzee do fast

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Answers

Answered by 217him217
1

Step-by-step explanation:

=>a^(q-r) *b^(r-p) *c^(p-q)

= (xy^(p-1))^(q-r) * (xy^(q-1))^(r-p) *(xy^(r-1))^(p-q)

= x^(q-r) *y^(pq-pr-q+r) * x^(r-p) *y^(qr-qp-r+p) * x^(p-q)*y^(rp-rq-p+q)

= x^(q-r+r-p+p-q) * y^(pq-pr-q+r+qr-qp-r+p+rp-rq-p+q)

= x^0*y^0

= 1

=> 2^x=3^y = 12^z = k

=> 2 = k^1/x

=> 3 = k^1/y

=> 12 = k^1/z

=> 2*2*3 = 12

=> k^2/x * k^1/y = k^1/z

=> 2/x + 1/y = 1/z

=> 2/x = 1/z - 1/y

=> 2/x = (y-z)/yz

=> x = 2yz/(y-z)

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