bounded by the axes of reference and the normal
to y=logex(log base e) at the point (1, 0) is
(a)1unitsquare (b)2unitsquare (c)1/2unit square (d)
none of these
karthikfriends4:
i need this solution for this problem..please, help me out..:)
Answers
Answered by
5
First of all find the equation of normal to curve at (1, 0)
This is slope of tangent so slope of normal is -1.
So equation of line -> (y - 0) = (-1) * (x - 1) -> x + y = 1
This is the line intersection x-axis at (1, 0) and y-axis at (0, 1), forming a right angle triangle with height = 1 unit and base = 1 unit.
So area =
Answer
(c)
This is slope of tangent so slope of normal is -1.
So equation of line -> (y - 0) = (-1) * (x - 1) -> x + y = 1
This is the line intersection x-axis at (1, 0) and y-axis at (0, 1), forming a right angle triangle with height = 1 unit and base = 1 unit.
So area =
Answer
(c)
Similar questions