Question

box contains (2 x + 7) sweets. how many sweets will (2x + 7) such boxes contain?​

Answer 1

$\huge\underline\red{SOLUTION}$

♠(2x+7)(2x+7)

♠2x²+14x+14x+49

♠4x²+28x+49

WE CAN GET ANSWER EASILY BY MULTIPLYING BOTH THE VALUES. SO, THE TOTAL NUMBER OF SWEETS CONTAINS IN SUCH BOXES IS "4X²+28X+49"

Answer 2

Answer:

It contains 4x^2+28x+49 sweets

Step-by-step explanation:

As per given question

No. of sweets in a box = 2x + 7

No. of sweets in (2x+7) boxes = (2x+7)(2x+7)

[(a+b)^2=a^2+2ab+b^2] = (2x+7)^2

=(2x)^2+2(2x)(7)+(7)^2

=4x^2 + 28x+49