Question

Box contains 3 gold and 4 silver coins. Another box contains 2 gold and 3 silver coins. A box is chosen at random, and a coin is drawn from it. If the selected coin is a gold coin, find the probability that it was drawn from the second box.

Answer 1

7/17 would be the probability of the gold coin being selected from the second box.

Step-by-step explanation:

Given that,

Let G be the gold coins while S as the silver

and the boxes to be A and B

G in box A = 3

S in box A = 4

G in box B = 2

S in box B= 3

Let the probability of selecting box as equal = 1/2

To find,

The Probability of the selected gold coin is from the second box = P(B/G)

P(B/G) = {(P(B) (P(G/B)}/P(A).P(G/A) + P(B). P(G/B)

= {(1/2) (2/5)}/{(4/7) (1/2) + (2/5) (1/2)

= (1/5)/{(4/14) + (2/10)}

= 7/17

Thus, 7/17 is the probability of taking the gold coin from the second box.

Learn more: find the probability

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