box contains 36 tickets bearing only one number from 1 to 36 on each. If one ticket is drawn at random, find the probability of an event that the ticket drawn bears (i) a number divisible by 5 (ii) a complete square number.
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0
Answer:
I think there will be 20 tickets
Step-by-step explanation:
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Answered by
1
Answer:
(i) Favourable outcome = 5,10,15,20,25,30,35
Probability = 7/36
(ii) Favourable outcome= 1, 4,9 16,25,36
Probability =6/36=1/6
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