Question

box contains 90 discs which are numbered from 1 to 90. If one disc is draw at random from the box.

Find the probability that it bears

(i) a one digit number

(ii) a perfect cube number

(iii) a number divisible by​

Answer 1

Answer:

(i) 1/10

(ii) 2/45

Step-by-step explanation:

formula of probability = ( No.of favorable outcomes / total possible outcomes )

total possible outcomes = 1 to 90 = 90

(i) one digit numbers from 1 to 90 are 1, 2, 3, 4, 5, 6, 7, 8, and 9 in total of 9. ( No. of favorable outcomes )

so, probability of getting a one digit on disc is = 9 / 90 = 1 / 10.

(ii) perfect cube numbers from 1 to 90 are 1 ( 1^3 ), 8 ( 2^3 ), 27 ( 3^3 ), and 64 ( 4^3 ) in total of 4. ( No. of favorable outcomes )

so, probability of getting a perfect cube digit on disc is = 4 / 90 = 2 / 45.

(iii) QUESTION IS INCOMPLETE.